5100-3x^2=0

Solution for 5100-3x^2=0 equation:

5100-3x^2=0

a = -3; b = 0; c = +5100;
Δ = b2-4ac
Δ = 02-4·(-3)·5100
Δ = 61200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61200}=\sqrt{3600*17}=\sqrt{3600}*\sqrt{17}=60\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{17}}{2*-3}=\frac{0-60\sqrt{17}}{-6}
=-\frac{60\sqrt{17}}{-6}
=-\frac{10\sqrt{17}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{17}}{2*-3}=\frac{0+60\sqrt{17}}{-6}
=\frac{60\sqrt{17}}{-6}
=\frac{10\sqrt{17}}{-1}
$